We can build our concept of limit with these .
Theorem 1:
If Lt (x → a ) f(x) = l and Lt (x → a ) g(x) = m c is a constant l,m,c are finite
1. Lt (x → a ) c*f(x) = c * l
2. Lt (x → a ) (f(x) + g(x)) = l + m
3 Lt (x → a ) f(x) * g(x) = l*m
Look carefully we assumed that individual limits of f(x) , g(x) for (x → a ) exist and limits are finite .
Theorem 2 : (Limit Inclusion Theorem)
If Lt (x → a ) f(x) = l and Lt (x → l ) g(x) = g(l) then Lt (x → a ) g(f(x)) = g(Lt (x → a ) f(x) ) = g(l)
Theorem 3:
If in Neighbourhood of x = a i.e. in Nbd(x = a) f(x) ≤ g(x) then Lt (x → a ) f(x) ≤ Lt (x → a ) g(x) .
Theorem 4: ( Sandwich Theorem )
If in Nbd(x = a) f(x) ≤ g(x) ≤ h(x) and Lt (x → a ) f(x) = Lt (x → a ) h(x) = l then Lt (x → a ) g(x) = l
Theorem 1:
If Lt (x → a ) f(x) = l and Lt (x → a ) g(x) = m c is a constant l,m,c are finite
1. Lt (x → a ) c*f(x) = c * l
2. Lt (x → a ) (f(x) + g(x)) = l + m
3 Lt (x → a ) f(x) * g(x) = l*m
Look carefully we assumed that individual limits of f(x) , g(x) for (x → a ) exist and limits are finite .
Theorem 2 : (Limit Inclusion Theorem)
If Lt (x → a ) f(x) = l and Lt (x → l ) g(x) = g(l) then Lt (x → a ) g(f(x)) = g(Lt (x → a ) f(x) ) = g(l)
Theorem 3:
If in Neighbourhood of x = a i.e. in Nbd(x = a) f(x) ≤ g(x) then Lt (x → a ) f(x) ≤ Lt (x → a ) g(x) .
Theorem 4: ( Sandwich Theorem )
If in Nbd(x = a) f(x) ≤ g(x) ≤ h(x) and Lt (x → a ) f(x) = Lt (x → a ) h(x) = l then Lt (x → a ) g(x) = l
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